# Find the Surface Area pyramid (6)(6)(8.5) h=6l=8.5w=6
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area lw, and sl and sw represent the slant height on the length and slant height on the width.
(length)⋅(width)+(width)⋅sl+(length)⋅sw
Substitute the values of the length l=8.5, the width w=6, and the height h=6 into the formula for surface area of a pyramid.
8.5⋅6+6⋅(8.52)2+(6)2+8.5⋅(62)2+(6)2
Simplify each term.
Multiply 8.5 by 6.
51+6⋅(8.52)2+(6)2+8.5⋅(62)2+(6)2
Divide 8.5 by 2.
51+6⋅4.252+(6)2+8.5⋅(62)2+(6)2
Raise 4.25 to the power of 2.
51+6⋅18.0625+(6)2+8.5⋅(62)2+(6)2
Raise 6 to the power of 2.
51+6⋅18.0625+36+8.5⋅(62)2+(6)2
Add 18.0625 and 36.
51+6⋅54.0625+8.5⋅(62)2+(6)2
Divide 6 by 2.
51+654.0625+8.5⋅32+(6)2
Raise 3 to the power of 2.
51+654.0625+8.5⋅9+(6)2
Raise 6 to the power of 2.
51+654.0625+8.5⋅9+36
Add 9 and 36.
51+654.0625+8.5⋅45
Rewrite 45 as 32⋅5.
Factor 9 out of 45.
51+654.0625+8.5⋅9(5)
Rewrite 9 as 32.
51+654.0625+8.5⋅32⋅5
51+654.0625+8.5⋅32⋅5
Pull terms out from under the radical.
51+654.0625+8.5⋅(35)
Multiply 8.5(35).
Multiply 3 by 8.5.
51+654.0625+25.55
Multiply 25.5 by 5.
51+654.0625+57.01973342
51+654.0625+57.01973342
51+654.0625+57.01973342
Simplify by adding terms.
Add 51 and 654.0625.
95.1163235+57.01973342
Add 95.1163235 and 57.01973342.
152.13605693
152.13605693
Calculate the approximate solution to 4 decimal places.
152.1361
Find the Surface Area pyramid (6)(6)(8.5)

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