Find the Surface Area pyramid (60)(60)(40)

Math
h=60l=40w=60
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area lw, and sl and sw represent the slant height on the length and slant height on the width.
(length)⋅(width)+(width)⋅sl+(length)⋅sw
Substitute the values of the length l=40, the width w=60, and the height h=60 into the formula for surface area of a pyramid.
40⋅60+60⋅(402)2+(60)2+40⋅(602)2+(60)2
Simplify each term.
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Multiply 40 by 60.
2400+60⋅(402)2+(60)2+40⋅(602)2+(60)2
Divide 40 by 2.
2400+60⋅202+(60)2+40⋅(602)2+(60)2
Raise 20 to the power of 2.
2400+60⋅400+(60)2+40⋅(602)2+(60)2
Raise 60 to the power of 2.
2400+60⋅400+3600+40⋅(602)2+(60)2
Add 400 and 3600.
2400+60⋅4000+40⋅(602)2+(60)2
Rewrite 4000 as 202⋅10.
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Factor 400 out of 4000.
2400+60⋅400(10)+40⋅(602)2+(60)2
Rewrite 400 as 202.
2400+60⋅202⋅10+40⋅(602)2+(60)2
2400+60⋅202⋅10+40⋅(602)2+(60)2
Pull terms out from under the radical.
2400+60⋅(2010)+40⋅(602)2+(60)2
Multiply 20 by 60.
2400+120010+40⋅(602)2+(60)2
Divide 60 by 2.
2400+120010+40⋅302+(60)2
Raise 30 to the power of 2.
2400+120010+40⋅900+(60)2
Raise 60 to the power of 2.
2400+120010+40⋅900+3600
Add 900 and 3600.
2400+120010+40⋅4500
Rewrite 4500 as 302⋅5.
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Factor 900 out of 4500.
2400+120010+40⋅900(5)
Rewrite 900 as 302.
2400+120010+40⋅302⋅5
2400+120010+40⋅302⋅5
Pull terms out from under the radical.
2400+120010+40⋅(305)
Multiply 30 by 40.
2400+120010+12005
2400+120010+12005
Calculate the approximate solution to 4 decimal places.
8878.0148
Find the Surface Area pyramid (60)(60)(40)

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