# Find the Surface Area pyramid (5.2)(6)(12) h=5.2l=12w=6
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area lw, and sl and sw represent the slant height on the length and slant height on the width.
(length)⋅(width)+(width)⋅sl+(length)⋅sw
Substitute the values of the length l=12, the width w=6, and the height h=5.2 into the formula for surface area of a pyramid.
12⋅6+6⋅(122)2+(5.2)2+12⋅(62)2+(5.2)2
Simplify each term.
Multiply 12 by 6.
72+6⋅(122)2+(5.2)2+12⋅(62)2+(5.2)2
Divide 12 by 2.
72+6⋅62+(5.2)2+12⋅(62)2+(5.2)2
Raise 6 to the power of 2.
72+6⋅36+(5.2)2+12⋅(62)2+(5.2)2
Raise 5.2 to the power of 2.
72+6⋅36+27.04+12⋅(62)2+(5.2)2
Add 36 and 27.04.
72+6⋅63.04+12⋅(62)2+(5.2)2
Divide 6 by 2.
72+663.04+12⋅32+(5.2)2
Raise 3 to the power of 2.
72+663.04+12⋅9+(5.2)2
Raise 5.2 to the power of 2.
72+663.04+12⋅9+27.04
Add 9 and 27.04.
72+663.04+1236.04
72+663.04+1236.04
Calculate the approximate solution to 4 decimal places.
191.6786
Find the Surface Area pyramid (5.2)(6)(12)

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