# Find the Surface Area pyramid (10)(8)(6) h=10l=6w=8
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area lw, and sl and sw represent the slant height on the length and slant height on the width.
(length)⋅(width)+(width)⋅sl+(length)⋅sw
Substitute the values of the length l=6, the width w=8, and the height h=10 into the formula for surface area of a pyramid.
6⋅8+8⋅(62)2+(10)2+6⋅(82)2+(10)2
Simplify each term.
Multiply 6 by 8.
48+8⋅(62)2+(10)2+6⋅(82)2+(10)2
Divide 6 by 2.
48+8⋅32+(10)2+6⋅(82)2+(10)2
Raise 3 to the power of 2.
48+8⋅9+(10)2+6⋅(82)2+(10)2
Raise 10 to the power of 2.
48+8⋅9+100+6⋅(82)2+(10)2
Add 9 and 100.
48+8⋅109+6⋅(82)2+(10)2
Divide 8 by 2.
48+8109+6⋅42+(10)2
Raise 4 to the power of 2.
48+8109+6⋅16+(10)2
Raise 10 to the power of 2.
48+8109+6⋅16+100
Add 16 and 100.
48+8109+6⋅116
Rewrite 116 as 22⋅29.
Factor 4 out of 116.
48+8109+6⋅4(29)
Rewrite 4 as 22.
48+8109+6⋅22⋅29
48+8109+6⋅22⋅29
Pull terms out from under the radical.
48+8109+6⋅(229)
Multiply 2 by 6.
48+8109+1229
48+8109+1229
Calculate the approximate solution to 4 decimal places.
196.1444
Find the Surface Area pyramid (10)(8)(6)

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