h=7mir=13mi

The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.

2π⋅(radius)2+2π⋅(radius)⋅(height)

Substitute the values of the radius r=13 and height h=7 into the formula. Pi π is approximately equal to 3.14.

2(π)(13)2+2(π)(13)(7)

Raise 13 to the power of 2.

2π⋅169+2(π)(13)(7)

Multiply 169 by 2.

338π+2(π)(13)(7)

Multiply 13 by 2.

338π+26π⋅7

Multiply 7 by 26.

338π+182π

338π+182π

Add 338π and 182π.

520π(mi)2

Find the Surface Area cylinder (7mi)(13mi)