# Find the Surface Area cylinder (7mi)(13mi) h=7mir=13mi
The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of π⋅r2, plus the area of the side. The area of the side is equal to the area of a rectangle with length 2πr (the circumference of the base) times the height.
Substitute the values of the radius r=13 and height h=7 into the formula. Pi π is approximately equal to 3.14.
2(π)(13)2+2(π)(13)(7)
Simplify each term.
Raise 13 to the power of 2.
2π⋅169+2(π)(13)(7)
Multiply 169 by 2.
338π+2(π)(13)(7)
Multiply 13 by 2.
338π+26π⋅7
Multiply 7 by 26.
338π+182π
338π+182π
Add 338π and 182π.
520π(mi)2
Find the Surface Area cylinder (7mi)(13mi)

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